r[items.type]

Type aliases

r[items.type.syntax]

TypeAlias ->
    `type` IDENTIFIER GenericParams? ( `:` TypeParamBounds )?
        WhereClause?
        ( `=` Type WhereClause?)? `;`

r[items.type.intro] A type alias defines a new name for an existing type in the type namespace of the module or block where it is located. Type aliases are declared with the keyword type. Every value has a single, specific type, but may implement several different traits, and may be compatible with several different type constraints.

For example, the following defines the type Point as a synonym for the type (u8, u8), the type of pairs of unsigned 8 bit integers:

#![allow(unused)]
fn main() {
type Point = (u8, u8);
let p: Point = (41, 68);
}

r[items.type.constructor-alias] A type alias to a tuple-struct or unit-struct cannot be used to qualify that type’s constructor:

#![allow(unused)]
fn main() {
struct MyStruct(u32);

use MyStruct as UseAlias;
type TypeAlias = MyStruct;

let _ = UseAlias(5); // OK
let _ = TypeAlias(5); // Doesn't work
}

r[items.type.associated-type] A type alias, when not used as an associated type, must include a [Type][grammar-Type] and may not include [TypeParamBounds].

r[items.type.associated-trait] A type alias, when used as an associated type in a trait, must not include a [Type][grammar-Type] specification but may include [TypeParamBounds].

r[items.type.associated-impl] A type alias, when used as an associated type in a trait impl, must include a [Type][grammar-Type] specification and may not include [TypeParamBounds].

r[items.type.deprecated] Where clauses before the equals sign on a type alias in a trait impl (like type TypeAlias<T> where T: Foo = Bar<T>) are deprecated. Where clauses after the equals sign (like type TypeAlias<T> = Bar<T> where T: Foo) are preferred.